Energy Efficient System’s Savings
Subject
Building Services
,Climatology
,Academic Year
2'nd Year
,Complexity Level
Intermediate
,Content tags
Carbon Footprinting
,Energy Consumption
,Energy Efficiency
,Activity Type
Numerical Exercise
,Activity duration
< 1 hour
,Objective
To estimate the energy and GHG emission savings from an energy efficient air conditioner.
Outcome
Students will realize that energy efficiency is a great way to save energy and GHG emissions and make the design choices accordingly.
Requirements
None
Prerequisites
Conceptual knowledge of
- Electrical energy consumption
- Carbon Footprinting
- Tonnage of Operational ACs in the college
Given Data
- Increase in efficiency of the Air conditioning system = 10%
- Average daily operation = 8 hrs
- Average monthly operation = 22 days
- Monthly energy consumption of a typical ceiling fan ~12 kWh
- Carbon Emission Factor for Electricity = 1.19 $$\frac{\:\text{kg CO2e}}{\:\text{kWh}}$$
- 1 tree absorbs approximately 250 kg of CO2 in its lifetime.
Procedure
Step 1: Students find out the total air conditioning load (TR – Ton of Refrigeration) of the campus.
Step 2: Convert TR to kW.
Step 3: Estimate the air conditioning energy consumption for a month.
Step 4: Select and determine energy savings for an energy efficient air conditioning system.
Step 5: Estimate the equivalent number of fans that can be operated due to these monthly savings.
Step 6: Estimate the GHG emissions saved (kg CO2e).
Step 7: Estimate the equivalent number of trees planted through electricity savings.
Sample Calculations
Step 1: Air conditioning load in college campus (TR) = 40 TR
Step 2: Air conditioning load in college campus (kW) = TR x 3.517
= 40 x 3.517
= 140.7 kW
Step 3: Air Conditioner’s monthly energy consumption (kWh)= Air Conditioning Load (kW) x avg. daily operation (hrs) x no. of operation days in a month
= 140.7 x 8 x 22
= 24,763 kWh
Step 4: Energy savings due to increase in efficiency (kWh) = % increase in energy efficiency x monthly energy consumption (kWh)
= 0.1 x 24,763
= 2,476 kWh
Step 5: Equivalent no. of fans that can be operated due to increased efficiency= $$\frac{\:\text{Energy savings due to increase in efficiency (kWh)}}{\:\text{Monthly energy consumption of a ceiling fan (kWh)}}$$
= $$\frac{\:\text{2476}}{\:\text{12}}$$
~206 fans
Step 6: GHG Emissions saved (kgCO2e) = Emission Factor for Electricity (kg CO2e/kWh) x Energy Savings (kWh)
= 1.19 x 2,476
= 2,947 kg CO2e
Step 7: Equivalent no. of trees planted =$$\frac{\:\text{GHG Emissions saved (kg CO2e)}}{\:\text{Carbon Absorption Capacity of one tree (kg CO2e)}}$$
= $$\frac{\:\text{2946.3}}{\:\text{250}}$$
~12 trees